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Two steel wires of the same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is 1:4, the ratio of their diameters is

Asked in JEE Main 9th Jan 2nd Shift 2020 · Energy stored in a stretched wire

Answer: (1) √2:1

Step-by-step solution

Given: the same length, the same material and the same load F for both wires; only the areas differ.

Idea: u=1/2(σ²)/Y with σ=F/A, so at fixed F and Y, u∝1/(A²)∝1/(d⁴).

Then (u₁)/(u₂)=((d₂)/(d₁))⁴=1/4, so ((d₁)/(d₂))⁴=4.

(d₁)/(d₂)=4^1/4=√2.

The ratio of diameters is √2:1.

Why the other options are wrong

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