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If S is the stress and Y is the Young's modulus of the material of a wire, the energy stored in the wire per unit volume is

Asked in AIEEE 2005 · Energy stored in a stretched wire

Answer: (4) (S²)/(2Y)

Step-by-step solution

Idea: for a wire loaded within the elastic limit, the energy stored per unit volume is the area under the stress-strain graph.

That area is one half of stress times strain, so u=1/2Sε.

From the definition of Young's modulus, ε=S/Y.

u=1/2S·S/Y=(S²)/(2Y).

Why the other options are wrong

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