Practice portal › Mechanical Properties of Solids › Wires in Series, Parallel and Tapering
Asked in JEE Main 25th July 1st Shift 2021 · Series and parallel wires
Given: two wires, each of length L and area A, joined end to end, so each carries the same load F and the elongations add.
Δℓ=(FL)/(AY₁)+(FL)/(AY₂).
The combination is one wire of length 2L and area A: Δℓ=(F(2L))/(AY_eq).
Equating, 2/(Y_eq)=1/(Y₁)+1/(Y₂).
Y_eq=(2Y₁Y₂)/(Y₁+Y₂).
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