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If the ratios of the lengths, radii and Young's moduli of the steel and brass wires in the figure are a, b and c respectively, then the corresponding ratio of the increase in their lengths is

Asked in JEE Main Online 2013 · Series and parallel wires

Figure: Series and parallel wires
Answer: (3) (3a)/(2b²c)

Step-by-step solution

Given: the steel wire hangs from the ceiling and carries the block M together with the block 2M below it, so Tₛₜₑₑₗ=3Mg, while the brass wire carries only the lower block, T_brass=2Mg.

Δℓ=(TL)/(π r²Y).

(Δℓₛₜₑₑₗ)/(Δℓ_brass)=(Tₛₜₑₑₗ)/(T_brass)·(Lₛₜₑₑₗ)/(L_brass)·((r_brass)/(rₛₜₑₑₗ))²·(Y_brass)/(Yₛₜₑₑₗ).

With a=(Lₛₜₑₑₗ)/(L_brass), b=(rₛₜₑₑₗ)/(r_brass), c=(Yₛₜₑₑₗ)/(Y_brass), this is 3/2· a·1/(b²)·1/c.

(Δℓₛₜₑₑₗ)/(Δℓ_brass)=(3a)/(2b²c).

Why the other options are wrong

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