Practice portal › Mechanical Properties of Solids › Elongation of a Single Wire
Asked in JEE Main 31st Jan 2nd Shift 2023 · Elongation under a load
Given: the same load F and the same extension Δ l for both wires.
Δ l=(FL)/(AY), so with F and Δ l fixed the combination L/(AY) is the same for both, giving Y∝L/A.
(Y_A)/(Y_B)=(L_A)/(L_B)×(A_B)/(A_A)=(5.0)/(6.0)×(3.0×10⁻⁵)/(2.5×10⁻⁵).
=5/6×6/5=1, so the ratio is 1:1.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer