The force required to stretch a wire of cross-section 1 cm² to double its length will be (Given Young's modulus of the wire =2×10¹¹ N m⁻²)

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(3) 2×10⁷ N. Given: A=1 cm²=10⁻⁴ m² and Y=2×10¹¹ N m⁻². Doubling the length means the extension equals the original length, so the strain is (Δ L)/L=1. F=YA(Δ L)/L=2×10¹¹×10⁻⁴×1. F=2×10⁷ N. In practice a wire snaps long before this, since a strain of 1 is far past the elastic limit; the question is about the formula, not about a real wire.

The force required to stretch a wire of cross-section 1 cm² to double its length will be (Given Young's modulus of the wire =2×10¹¹ N m⁻²)

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