Practice portal › Mechanical Properties of Fluids › Surface Tension and Surface Energy
Asked in AIEEE 2011 · Work done on a soap bubble
Given: T=0.03 N m⁻¹, r₁=0.03 m, r₂=0.05 m.
Two surfaces on a soap bubble, so W=8π T(r₂²-r₁²).
r₂²-r₁²=25×10⁻⁴-9×10⁻⁴=16×10⁻⁴ m².
W=8π(0.03)(16×10⁻⁴)=3.84×10⁻⁴π J=0.384π mJ.
That is nearly 0.4π mJ.
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