Practice portal › Mechanical Properties of Fluids › Surface Tension and Surface Energy

A water drop of diameter 2 cm is broken into 64 equal droplets. The surface tension of water is 0.075 N m⁻¹. In this process the gain in surface energy will be

Asked in JEE Main 28th June 2nd Shift 2022 · Splitting a drop

Answer: (1) 2.8×10⁻⁴ J

Step-by-step solution

Given: diameter 2 cm, so R=10⁻² m; n=64; T=0.075 N m⁻¹.

Equal volume gives r=R/(n^1/3)=R/4, so the total area grows by the factor n^1/3=4.

Gain =4π R²T(n^1/3-1), with 4π R²T=4π(10⁻⁴)(0.075)=9.42×10⁻⁵ J.

Δ E=9.42×10⁻⁵×3=2.83×10⁻⁴ J.

That is 2.8×10⁻⁴ J.

Why the other options are wrong

More Surface Tension and Surface Energy questionsAll Surface Tension and Surface Energy questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer