Practice portal › Mechanical Properties of Fluids › Surface Tension and Surface Energy
Asked in JEE Main 28th June 2nd Shift 2022 · Splitting a drop
Given: diameter 2 cm, so R=10⁻² m; n=64; T=0.075 N m⁻¹.
Equal volume gives r=R/(n^1/3)=R/4, so the total area grows by the factor n^1/3=4.
Gain =4π R²T(n^1/3-1), with 4π R²T=4π(10⁻⁴)(0.075)=9.42×10⁻⁵ J.
Δ E=9.42×10⁻⁵×3=2.83×10⁻⁴ J.
That is 2.8×10⁻⁴ J.
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