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An air bubble of radius 1 cm in water has an upward acceleration 9.8 cm s⁻². The density of water is 1 gm cm⁻³ and water offers negligible drag force on the bubble. The mass of the bubble is (g=980 cm s⁻²)

Asked in JEE Main 4th Sept 1st Shift 2020 · Floating and submerged bodies

Answer: (3) 4.15 gm

Step-by-step solution

Given: r=1 cm, ρ_w=1 gm cm⁻³, a=9.8 cm s⁻² upward, g=980 cm s⁻², drag negligible.

The bubble's volume is V=4/3π r³=4/3π=4.19 cm³, so the upthrust is ρ_wVg.

Newton's second law on the bubble, taking up as positive: ρ_wVg-mg=ma.

m=(ρ_wVg)/(g+a)=(4.19×980)/(989.8).

m=4.15 gm, just under the 4.19 gm of water displaced, as it must be for the bubble to accelerate upward.

Why the other options are wrong

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