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A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water? [Take density of water =10³ kg m⁻³]

Asked in JEE Main 10th April 2nd Shift 2019 · Floating and submerged bodies

Answer: (3) 87.5 kg

Step-by-step solution

Given: cube of side 0.5 m, so V=0.125 m³, floating with 30% submerged, ρ_w=10³ kg m⁻³.

Floating as it is, the block's own mass equals the water it displaces: m=ρ_w(0.30V)=10³×0.0375=37.5 kg.

Just fully submerged, the displacement is the whole cube: ρ_wV=10³×0.125=125 kg of water.

The extra load is the difference between what it can displace and what it already weighs.

M=125-37.5=87.5 kg.

Why the other options are wrong

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