A current of 5 A exists in a square loop of side 1/(√2) m. Then the magnitude of the magnetic field B at the centre of the square loop will be p×10⁻⁶ T, where, value of p is . [Take μ₀=4π×10⁻⁷ T m A⁻¹]

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8. Square of side a: B=(2√2μ₀ I)/(π a). B=(2√2×4π×10⁻⁷×5)/(π/√2)=8×10⁻⁶ T → 8

A current of 5 A exists in a square loop of side 1/(√2) m. Then the magnitude of the magnetic field B at the centre of the square loop will be p×10⁻⁶ T, where, value of p is ______. [Take μ₀=4π×10⁻⁷ T m A⁻¹]

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