A straight wire carrying a current of 14 A is bent into a semicircular arc of radius 2.2 cm as shown in the figure. The magnetic field produced by the current at the centre (O) of the arc, is ×10⁻⁴ T.

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2. The straight parts lie along the line through O: no field. Semicircle: B=(μ₀ I)/(4R)=(4π×10⁻⁷×14)/(4×0.022). B=(π×14×10⁻⁷)/(0.022)≈2×10⁻⁴ T → 2

A straight wire carrying a current of 14 A is bent into a semicircular arc of radius 2.2 cm as shown in the figure. The magnetic field produced by the current at the centre (O) of the arc, is ______ ×10⁻⁴ T.

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