Practice portal › Moving Charges and Magnetism › Biot-Savart Law: Straight Wires and Arcs
Asked in JEE Main 23rd Jan 2nd Shift 2026 · Straight wire segments
Centroid to side distance d=a/(2√3)=(4√3)/(2√3)=2 cm
Each side subtends 60° on either side: B₁=(μ₀ I)/(4π d)(2 sin 60°)=(10⁻⁷×2)/(0.02)√3=√3×10⁻⁵ T
Three sides add: B=3√3×10⁻⁵ T, so α=3√3
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