A 1 μC charge moving with velocity v⃗=(ı̂-2ȷ̂+3k̂) m/s in the region of magnetic field B⃗=(2ı̂+3ȷ̂-5k̂) T. The magnitude of the force acting on it is √α×10⁻⁶ N. The value of α is .

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Accepted Answer

171. F⃗=q(v⃗×B⃗) v⃗×B⃗=ı̂[(-2)(-5)-(3)(3)]-ȷ̂[(1)(-5)-(3)(2)]+k̂[(1)(3)-(-2)(2)]=ı̂+11ȷ̂+7k̂ |v⃗×B⃗|=√1+121+49=√171 F=10⁻⁶√171 N, so α=171 → 171

A 1 μC charge moving with velocity v⃗=(ı̂-2ȷ̂+3k̂) m/s in the region of magnetic field B⃗=(2ı̂+3ȷ̂-5k̂) T. The magnitude of the force acting on it is √α×10⁻⁶ N. The value of α is ______.

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