A charge of 4.0 μC is moving with a velocity of 4.0×10⁶ m s⁻¹ along the positive y-axis under a magnetic field B⃗ of strength (2k̂) T. The force acting on the charge is xı̂ N. The value of x is .

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Accepted Answer

32. F⃗=qv⃗×B⃗=(4×10⁻⁶)(4×10⁶)(2)(ȷ̂×k̂) ȷ̂×k̂=ı̂, so F⃗=32ı̂ N → 32

A charge of 4.0 μC is moving with a velocity of 4.0×10⁶ m s⁻¹ along the positive y-axis under a magnetic field B⃗ of strength (2k̂) T. The force acting on the charge is xı̂ N. The value of x is ______.

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