Practice portal › Moving Charges and Magnetism › Force on a Moving Charge
Asked in JEE Main 6th Sept 2nd Shift 2020 · Lorentz force and work done
ma⃗ = F⃗; F⃗ · v⃗ = 2kvₓv_y eq 0, so not magnetic and kinetic energy changes.
v⃗ × a⃗ = k/m(vₓ² - v_y²)k̂.
d/(dt)(vₓ² - v_y²) = 2vₓ(kv_y)/m - 2v_y(kvₓ)/m = 0.
So v⃗ × a⃗ is constant.
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