Proton with kinetic energy of 1 MeV moves from south to north. It gets an acceleration of 10¹² m/s² by an applied magnetic field (west to east). The value of magnetic field (Rest mass of proton is 1.6 × 10⁻²⁷ kg)

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(4) 0.71 mT. K = 1 MeV = 1.6 × 10⁻¹³ J; v = √(2K)/m = √2 × 10¹⁴ ≈ 1.41 × 10⁷ m/s. ma = evB, so B = (ma)/(ev). B = (1.6 × 10⁻²⁷ × 10¹²)/(1.6 × 10⁻¹⁹ × 1.41 × 10⁷) ≈ 7.1 × 10⁻⁴ T = 0.71 mT.

Proton with kinetic energy of 1 MeV moves from south to north. It gets an acceleration of 10¹² m/s² by an applied magnetic field (west to east). The value of magnetic field (Rest mass of proton is 1.6 × 10⁻²⁷ kg)

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