A stone of mass 1 kg is tied to end of a massless string of length 1 m. If the breaking tension of the string is 400 N, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is

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Accepted Answer

(2) 20 m s⁻¹. Idea: the tension is the centripetal force, T=(mv²)/r. 400=(1× v²)/1 v²=400, so v=20 m s⁻¹. Option (c) is v² itself, which is the single most common way to lose this question. The stone's weight is neglected here, as the phrase 'in horizontal plane' invites: at 400 N of tension the 9.8 N of weight tilts the string by barely more than a degree.

A stone of mass 1 kg is tied to end of a massless string of length 1 m. If the breaking tension of the string is 400 N, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is

Step-by-step solution

Why the other options are wrong