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A boy ties a stone of mass 100 g to the end of a 2 m long string and whirls it around in a horizontal plane. The string can withstand the maximum tension of 80 N. If the maximum speed with which the stone can revolve is K/π rev./min. The value of K is (Assume the string is massless and unstretchable)

Asked in JEE Main 24th June 1st Shift 2022 · Whirling a stone, a spring or a rod

Answer: (3) 600

Step-by-step solution

Idea: get ω from the tension, then convert radians per second into revolutions per minute — the conversion is the whole question.

T=mω²r:

80=0.1×ω²×2=0.2 ω²

ω²=400, so ω=20 rad/s.

In revolutions per minute,

n=ω/(2π)×60=(20×60)/(2π)=(600)/π rev/min.

Comparing with K/π gives K=600.

Leaving the answer as (600)/π rather than 191 rpm is the examiner's way of checking that the factor (60)/(2π) was applied and not (60)/π.

Why the other options are wrong

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