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Asked in JEE Main 11th April 2nd Shift 2023 · Speed with temperature and molar mass
Per molecule, vᵣₘₛ=√(3k_BT)/m.
T=27+273=300 K.
3k_BT=3×1.4×10⁻²³×300=1.26×10⁻²⁰.
(3k_BT)/m=(1.26×10⁻²⁰)/(4.6×10⁻²⁶)=2.74×10⁵.
vᵣₘₛ=√2.74×10⁵≈523 m/s.
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