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Given below are two statements. Statement I: The average momentum of a molecule in a sample of an ideal gas depends on temperature. Statement II: The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v. In the light of the above statements, choose the correct answer from the options given below.

Asked in JEE Main 28th July 1st Shift 2022 · Dissociation and rms speed

Answer: (4) Statement I is false but Statement II is true.

Step-by-step solution

Statement I: momentum is a vector, and in equilibrium molecules move equally in every direction.

The average momentum of a molecule is therefore zero at every temperature. Statement I is false.

Statement II: start with v=√(3RT)/(32) for O₂.

After dissociation M=16, and the temperature is 2T: v'=√(3R(2T))/(16)=√(3RT)/8.

(v')/v=√(32)/8=2, so v'=2v. Statement II is true.

Why the other options are wrong

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