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Asked in JEE Main 28th July 1st Shift 2022 · Dissociation and rms speed
Statement I: momentum is a vector, and in equilibrium molecules move equally in every direction.
The average momentum of a molecule is therefore zero at every temperature. Statement I is false.
Statement II: start with v=√(3RT)/(32) for O₂.
After dissociation M=16, and the temperature is 2T: v'=√(3R(2T))/(16)=√(3RT)/8.
(v')/v=√(32)/8=2, so v'=2v. Statement II is true.
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