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A vessel contains 16 g of hydrogen and 128 g of oxygen at standard temperature and pressure. The volume of the vessel in cm³ is

Asked in JEE Main 29th June 2nd Shift 2022 · Ideal gas equation and mixtures

Answer: (3) 27 × 10⁴

Step-by-step solution

Hydrogen: n₁=(16)/2=8 mol. Oxygen: n₂=(128)/(32)=4 mol.

Total n=12 mol.

At STP one mole occupies 22400 cm³.

V=12×22400=268800 cm³≈27×10⁴ cm³.

Why the other options are wrong

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