A mixture of hydrogen and oxygen has volume 500 cm³, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be

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(1) 16 : 3. Total moles: n=(PV)/(RT)=(4×10⁵×5×10⁻⁴)/(8.31×300)=(200)/(2493)=0.0802 mol. With a moles of H₂ and b of O₂: a+b=0.0802 and 2a+32b=0.76. Solving, a=0.0603 and b=0.0200, so the mole ratio is 3:1. Masses are moles times molar mass: m_O₂:m_H₂=(1×32):(3×2)=32:6. =16:3.

A mixture of hydrogen and oxygen has volume 500 cm³, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be

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