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Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. T₁ and T₂ are the total flying times of first and second ball, respectively, then the ratio of T₁ and T₂ is

Asked in JEE Main 8th April 2nd Shift 2025 · Maximum height

Answer: (1) 2√2 : 1

Step-by-step solution

H = (u_y²)/(2g) and T = (2u_y)/g, so T ∝ √H.

(T₁)/(T₂) = √8 = 2√2.

Why the other options are wrong

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