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Two projectiles are fired with same initial speed from same point on ground at angles of (45° - α) and (45° + α), respectively, with the horizontal direction. The ratio of their maximum heights attained is

Asked in JEE Main 29th Jan 1st Shift 2025 · Maximum height

Answer: (2) (1 - sin 2α)/(1 + sin 2α)

Step-by-step solution

H ∝ sin²θ and sin²(45° ∓ α) = (1 - cos(90° ∓ 2α))/2 = (1 ∓ sin 2α)/2.

(H₁)/(H₂) = (1 - sin 2α)/(1 + sin 2α).

Why the other options are wrong

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