Practice portal › Motion in a Straight Line › Sketching and Matching Motion Graphs
Asked in JEE Main 16th March 1st Shift 2021 · Sketching and matching motion graphs
0 to 200 m: v rises linearly from 10 to 50 m/s, so v = 10 + 0.2x and (dv)/(dx) = 0.2 s⁻¹.
a = v(dv)/(dx) = 0.2(10 + 0.2x) = 2 + 0.04x: a straight line from 2 m/s² at x = 0 to 2 + 8 = 10 m/s² at x = 200 m.
200 to 400 m: v is constant, so a = 0.
Graph (d): a straight ramp from 2 to 10, then zero. (The printed option panels label the top level 18; the physics gives 10, and the figure is drawn with 10.)
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