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A tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height /h2. The velocity versus height of the ball during its motion may be represented graphically by (graphs are drawn schematically and not to scale)

Asked in JEE Main 4th Sept 1st Shift 2020 · Sketching and matching motion graphs

Figure: Sketching and matching motion graphs
Answer: (4) Graph (d)

Step-by-step solution

Take upward as positive. Falling from h: v = -√2g(h - y), negative and growing in size as the height y shrinks to zero.

In the v–h plane that is a parabola (y = h - v²/2g) running from (h, 0) down to (0, -√2gh).

After the bounce the ball rises with a smaller positive speed: v = +√2g(h/2 - y), another parabola from (0, +√gh) up to (h/2, 0).

Two curved branches, the lower one (negative v) reaching h, the upper one (positive v) ending at h/2: graph (d).

Why the other options are wrong

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