Water drops fall from a tap on the floor, 5 m below, at regular intervals of time, the first drop strikes the floor when the sixth drop begins to fall. The height at which the fourth drop will be from ground, at the instant when the first drop strikes the ground is m. (g = 10 m/s²)

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(3) 4.2. Let the interval between drops be τ. When the sixth drop starts, the first has been falling for 5τ. First drop: 5 = 1/2×10×(5τ)² = 125τ² ⇒ τ = 0.2 s. The fourth drop has been falling for 2τ = 0.4 s: distance = 5×0.4² = 0.8 m. Height above the floor = 5 - 0.8 = 4.2 m.

Water drops fall from a tap on the floor, 5 m below, at regular intervals of time, the first drop strikes the floor when the sixth drop begins to fall. The height at which the fourth drop will be from ground, at the instant when the first drop strikes the ground is ______ m. (g = 10 m/s²)

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