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A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

Asked in JEE Main 29th July 2nd Shift 2022 · Two bodies under gravity

Answer: (4) g/2n²

Step-by-step solution

n balls per second means one throw every 1/n s, and that interval is the time for a ball to reach the top.

Time to the top = /ug = 1/n ⇒ u = /gn.

Maximum height H = (u²)/(2g) = g/(2n²).

Why the other options are wrong

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