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The escape velocity of a body on a planet A is 12 km s⁻¹. The escape velocity of the body on another planet B, whose density is four times and radius is half of the planet A, is

Asked in JEE Main 29th June 1st Shift 2022 · Comparing planets

Answer: (1) 12 km s⁻¹

Step-by-step solution

Write the escape speed in terms of density by putting M=4/3π R³ρ into vₑ=√(2GM)/R.

vₑ=R√(8π Gρ)/3, so vₑ∝ R√ρ.

For B: (v_B)/(v_A)=1/2×√4=1.

The two effects cancel, so v_B=12 km s⁻¹.

Why the other options are wrong

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