Practice portal › Gravitation › Escape Velocity
Asked in JEE Main 1st Feb 2nd Shift 2023 · Comparing planets
Escape speed and surface gravity are linked through vₑ=√2gR, so vₑ²=2gR.
Hence g=(vₑ²)/(2R) and (g_A)/(g_B)=(v_A²)/(v_B²)·(R_B)/(R_A).
(g_A)/(g_B)=(1/2)²×3/1=3/4.
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