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Two particles of equal mass m move in a circle of radius r under the action of their mutual gravitational attraction. The speed of each particle will be

Asked in JEE Main 29th Jan 1st Shift 2023 (also AIEEE Re-Scheduled 2011) · Mutual gravitation and binary systems

Answer: (2) √(Gm)/(4r)

Step-by-step solution

The two particles stay at opposite ends of a diameter, so they are 2r apart while each orbits on a circle of radius r.

Their mutual attraction provides the centripetal force: (Gm²)/((2r)²)=(mv²)/r.

v²=(Gm)/(4r).

So v=√(Gm)/(4r).

Why the other options are wrong

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