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A load of mass M kg is suspended from a steel wire of length 2 m and radius 1.0 mm in Searle's apparatus experiment. The increase in length produced in the wire is 4.0 mm. Now the load is fully immersed in a liquid of relative density 2. The relative density of the material of load is 8. The new value of increase in length of the steel wire is

Asked in JEE Main 12th Jan 2nd Shift 2019 · Searle's apparatus and the set-up

• (1) 4.0 mm
• (2) zero
• (3) 5.0 mm
• (4) 3.0 mm

Step-by-step solution

Why the other options are wrong

• (1) comes from assuming the buoyant force acts on the wire rather than on the load, so nothing changes
• (2) comes from treating the load as fully supported by the liquid, which would need the two densities to be equal
• (3) comes from multiplying by 8/(2×) the wrong way round, i.e. using 1+1/4 instead of 1-1/4

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