Young's modulus is determined by the equation given by Y=49000M/l (dyne)/(cm²), where M is the mass and l is the extension of wire used in the experiment. Now error in Young's modulus (Y) is estimated by taking data from M-l plot in graph paper. The smallest scale divisions are 5 g and 0.02 cm alon…

Question

Young's modulus is determined by the equation given by Y=49000M/l (dyne)/(cm²), where M is the mass and l is the extension of wire used in the experiment. Now error in Young's modulus (Y) is estimated by taking data from M-l plot in graph paper. The smallest scale divisions are 5 g and 0.02 cm along load axis and extension axis, respectively. If the value of M and l are 500 g and 2 cm, respectively then percentage error of Y is

Accepted Answer

(4) 2%. Given: Δ M=5 g on M=500 g; Δ l=0.02 cm on l=2 cm. Y∝M/l, so (Δ Y)/Y=(Δ M)/M+(Δ l)/l. =5/(500)+(0.02)/2=0.01+0.01=0.02. Percentage error =2%.

Step-by-step solution

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