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The radiation pressure exerted by a 450 W light source on a perfectly reflecting surface placed at 2 m away from it, is

Asked in JEE Main 3rd April 1st Shift 2025 · Force and radiation pressure

Answer: (4) 6 × 10⁻⁸ Pascals

Step-by-step solution

Treat the source as a point source: I = P/(4π r²) = 450/(4π × 2²) = 450/50.27 = 8.95 W m⁻²

Perfectly reflecting ⇒ p_rad = 2I/c = 2 × 8.95/(3 × 10⁸) = 5.97 × 10⁻⁸ Pa

Why the other options are wrong

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