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Average force exerted on a non-reflecting surface at normal incidence is 2.4 × 10⁻⁴ N. If 360 W/cm² is the light energy flux during span of 1 hour 30 minutes, then the area of the surface is

Asked in JEE Main 8th April 1st Shift 2024 · Force and radiation pressure

Answer: (3) 0.02 m²

Step-by-step solution

Non-reflecting (complete absorption) ⇒ F = IA/c, so A = Fc/I

I = 360 W cm⁻² = 360 × 10⁴ = 3.6 × 10⁶ W m⁻²

A = 2.4 × 10⁻⁴ × 3 × 10⁸ / (3.6 × 10⁶) = 7.2 × 10⁴/(3.6 × 10⁶) = 0.02 m² — the 1 h 30 min span is already inside the average force

Why the other options are wrong

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