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An alternating voltage of amplitude 40 V and frequency 4 kHz is applied directly across the capacitor of 12 μF. The maximum displacement current between the plates of the capacitor is nearly

Asked in JEE Main 5th April 1st Shift 2024 · Capacitor on an a.c. source

Answer: (4) 12 A

Step-by-step solution

i_d0 = i_c0 = V₀/X_C = ω CV₀

ω = 2π × 4 × 10³ = 2.513 × 10⁴ rad s⁻¹

i_d0 = 2.513 × 10⁴ × 12 × 10⁻⁶ × 40 = 12.06 A ≈ 12 A

Why the other options are wrong

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