Practice portal › Electromagnetic Waves › Displacement Current
Asked in JEE Main 1st Feb 1st Shift 2024 · Capacitor on an a.c. source
X_C = 1/(ω C) = 1/(300 × 200 × 10⁻¹²) = 1.667 × 10⁷ Ω
Iᵣₘₛ = Vᵣₘₛ/X_C = 230/(1.667 × 10⁷) = 1.38 × 10⁻⁵ A = 13.8 μA
i_d = i_c at every instant, so the displacement current is the same 13.8 μA
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