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Asked in JEE Main 23rd Jan 2nd Shift 2026 · Dielectric slab
The battery stays connected, so V is fixed and (Q')/Q=(C')/C=1.25.
With a partially filling slab, C'=(ε₀A)/(d-t+t/K) while C=(ε₀A)/d, so (C')/C=d/(d-t+t/K).
5/(3+2/K)=1.25⇒ 3+2/K=5/(1.25)=4.
2/K=1, so K=2.0.
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