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Asked in JEE Main 8th April 2nd Shift 2019 · Oscillation of a dipole
For a small angular displacement θ from the aligned position, the restoring torque is τ=-pE sin θ≈-pEθ, with p=qd.
The dipole rotates about its centre of mass, which is the midpoint, so each charge is at d/2 and I=2m(d/2)²=(md²)/2.
Iθ=-pEθ gives ω²=(pE)/I=(qdE)/(md²/2)=(2qE)/(md).
ω=√(2qE)/(md).
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