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Asked in JEE Main 12th Jan 1st Shift 2019 · Dipole moment and dipole field
Take the base vertices at (0,0) and (l,0), each carrying +q, and the apex at (l/2,(√3 l)/2) carrying -2q.
The system is neutral, so ⃗p=Σ qᵢ⃗rᵢ may be computed about any origin.
x-component: q(0)+q(l)+(-2q)l/2=ql-ql=0.
y-component: q(0)+q(0)+(-2q)(√3 l)/2=-√3 ql.
⃗p=-√3 ql ̂j, i.e. of magnitude √3 ql pointing from the -2q apex down towards the base, as a dipole moment must point from negative to positive charge.
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