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A particle moving with kinetic energy E has de Broglie wavelength λ. If energy Δ E is added to its energy, the wavelength becomes λ/2. Value of Δ E is

Asked in JEE Main 9th Jan 1st Shift 2020 · Same or changed energy

Answer: (3) 3E

Step-by-step solution

λ∝1/(√E), so halving the wavelength quadruples the energy.

E'=4E.

Δ E=E'-E=3E.

Why the other options are wrong

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