In an electron microscope, the resolution that can be achieved is of the order of the wavelength of electrons used. To resolve a width of 7.5×10⁻¹² m, the minimum electron energy required is close to

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(1) 25 keV. p=h/λ=(6.63×10⁻³⁴)/(7.5×10⁻¹²)=8.84×10⁻²³ kg m s⁻¹. K=(p²)/(2m)=((8.84×10⁻²³)²)/(2×9.1×10⁻³¹)=4.3×10⁻¹⁵ J. K=(4.3×10⁻¹⁵)/(1.6×10⁻¹⁹)≈27 keV, closest to 25 keV.

In an electron microscope, the resolution that can be achieved is of the order of the wavelength of electrons used. To resolve a width of 7.5×10⁻¹² m, the minimum electron energy required is close to

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