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An α particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particles will be

Asked in JEE Main 29th July 2nd Shift 2022 · Accelerated through a potential difference

Answer: (2) 2√2:1

Step-by-step solution

p=√2mqV.

(p_α)/(pₚ)=√(m_α q_α)/(mₚqₚ)=√4×2=√8.

√8=2√2, so the ratio is 2√2:1.

Why the other options are wrong

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