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A particle A of mass m and charge q is accelerated by a potential difference of 50 V. Another particle B of mass 4m and charge q is accelerated by a potential difference of 2500 V. The ratio of de Broglie wavelength (λ_A)/(λ_B) is close to

Asked in JEE Main 12th Jan 1st Shift 2019 · Accelerated through a potential difference

Answer: (1) 14.14

Step-by-step solution

λ=h/(√2mqV), so λ∝1/(√mV) at equal charge.

(λ_A)/(λ_B)=√(m_BV_B)/(m_AV_A)=√(4m×2500)/(m×50).

=√200=14.14.

Why the other options are wrong

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