Practice portal › Dual Nature of Matter and Radiation › de Broglie Wavelength and Accelerating Potential
Asked in JEE Main 12th Jan 1st Shift 2019 · Accelerated through a potential difference
λ=h/(√2mqV), so λ∝1/(√mV) at equal charge.
(λ_A)/(λ_B)=√(m_BV_B)/(m_AV_A)=√(4m×2500)/(m×50).
=√200=14.14.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer