Given figure shows few data points in a photoelectric effect experiment for a certain metal. The minimum energy for ejection of electrons from its surface is (Planck's constant h=6.62×10⁻³⁴ J s)

Question

Accepted Answer

(2) 2.10 eV. Idea: the line meets the frequency axis at the threshold, where the stopping potential is zero. Point B sits on that axis at 
u₀=5.5×10¹⁴ Hz. φ=h
u₀=6.62×10⁻³⁴×5.5×10¹⁴=3.64×10⁻¹⁹ J. φ=(3.64×10⁻¹⁹)/(1.6×10⁻¹⁹)=2.27 eV. This is option (a), not the printed key (b); the disagreement is recorded in DEFECTS.

Given figure shows few data points in a photoelectric effect experiment for a certain metal. The minimum energy for ejection of electrons from its surface is (Planck's constant h=6.62×10⁻³⁴ J s)

Step-by-step solution

Why the other options are wrong