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In photoelectric experiment energy of 2.48 eV irradiates a photo sensitive material. The stopping potential was measured to be 0.5 V. Work function of the photo sensitive material is

Asked in JEE Main 6th April 1st Shift 2024 · Work function and the photoelectric equation

Answer: (4) 1.98 eV

Step-by-step solution

Given: E=2.48 eV, V₀=0.5 V so Kₘₐₓ=0.5 eV.

φ=E-Kₘₐₓ=2.48-0.5.

φ=1.98 eV.

Why the other options are wrong

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