Two cells are connected in opposition as shown. Cell E₁ is of 8 V emf and 2 Ω internal resistance, the cell E₂ is of 2 V emf and 4 Ω internal resistance. The terminal potential difference of cell E₂ is V. [Figure: a single loop. Along the top, from point A: cell E₁, then point B, then cell E₂, then…

Question

Two cells are connected in opposition as shown. Cell E₁ is of 8 V emf and 2 Ω internal resistance, the cell E₂ is of 2 V emf and 4 Ω internal resistance. The terminal potential difference of cell E₂ is V. [Figure: a single loop. Along the top, from point A: cell E₁, then point B, then cell E₂, then point C; the two cells face opposite ways. A plain wire closes the loop from C round the bottom back to A.]

Accepted Answer

6. Opposing cells: net emf =8-2=6 V, total resistance =2+4=6 Ω. I=6/6=1 A, driven by E₁. This current enters E₂ at its positive terminal, so E₂ is being charged. Terminal voltage of E₂: V=E₂+Ir₂=2+1×4=6 V.

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