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Two identical cells each of emf 1.5 V are connected in series across a 10 Ω resistance. An ideal voltmeter connected across 10 Ω resistance reads 1.5 V. The internal resistance of each cell is ______ Ω.

Asked in JEE Main 11th April 2nd Shift 2023 · Terminal voltage and internal resistance

Answer: 5

Step-by-step solution

Current: I=(1.5)/(10)=0.15 A.

Total emf 3 V: 3=0.15(10+2r).

10+2r=20, so r=5 Ω.

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