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In Young's double slit experiment the distance between the two slits is 0.2 mm and the distance between the slits and the screen is 1.5 m. The wavelength of the light used is 600 nm. The distance between any two consecutive bright fringes is ________ mm.

Asked in GSEB Board March 2023 · Fringe width and fringe position

Answer: (2) 4.5

Step-by-step solution

Given: d = 0.2 mm = 2×10⁻⁴ m, D = 1.5 m, λ = 600 nm = 6×10⁻⁷ m.

Idea: consecutive bright fringes are one fringe width apart, and that width is β = (λ D)/d.

β = ((6×10⁻⁷)(1.5))/(2×10⁻⁴) = (9×10⁻⁷)/(2×10⁻⁴).

β = 4.5×10⁻³ m.

Consecutive bright fringes are 4.5 mm apart.

Why the other options are wrong

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