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Asked in GSEB Board March 2023 · Fringe width and fringe position
Given: d = 0.2 mm = 2×10⁻⁴ m, D = 1.5 m, λ = 600 nm = 6×10⁻⁷ m.
Idea: consecutive bright fringes are one fringe width apart, and that width is β = (λ D)/d.
β = ((6×10⁻⁷)(1.5))/(2×10⁻⁴) = (9×10⁻⁷)/(2×10⁻⁴).
β = 4.5×10⁻³ m.
Consecutive bright fringes are 4.5 mm apart.
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